Good point about the x and y axes.It's been a few decades!
Your extrapolations using the ratio areas make sense to me, as the rectangle of the proportions has to fit within the circumference of the circle of the FOV. Now go out and fly, to confirm it!![]()
But @WithTheBirds has suggested that your calculations might have determined the hypotenuse instead of the x dimension as I supposed.
If the FOV is stated as 94 degrees, does that take the sensor into account or only the lens? If only the lens, how do we know how much of that falls upon the sensor.
I also had been picturing the field of view as a rectangle which is why i thought your calculations would refer to the widest dimension - but hearing you call it a circle reminded me the lens itself is round so I think @WithTheBirds is probably right that the FOV is the diagonal (hypotenuse) and we need to do some extra math to get length and width.
C^2 = 2.144 * height
A^2 + B^2 = C^2
For a 4:3 ratio sensor, we have a 3,4,5 triangle - so to make things easy, to get 50 for our hypotenuse, our height would be:
50 / 2.144 = 23.3208m
Therefore at 23.32m altitude, the captured area on the ground would be 40m x 30m!
Did I screw that up?